8.46.) A random render of 10 miniature Tootsie Rolls was construe from a bag. Each piece was weighed on a actually accurate scale. The results in grams were 3.087 3.131 3.241 3.241 3.270 3.353 3.400 3.411 3.437 3.477 (a) Construct a 90 heap confidence breakup for the true mean cant over. E = 1.96(s/sqrt(n)) = 1.96[0.131989/sqrt(10)]=1.96*0.41739 =0.081808 C.I. = (x-bar-E,x-bar+E) = (3.3048-0.0818,3.3048+0.0818) (b) What model sizing would be necessary to estimate the true charge with an error of ± 0.03 grams with 90 percentage confidence? n=[z*s/E]^2 n=[1.645*0.131989/0.03]^2 = 52.38; rounding up, n=53 (c) Discuss the work outs which skill cause alteration in the weight of Tootsie Rolls during manufacture. The equipment that the Tootsie Rolls are make on could be a factor if they are non calibrated properly or as intended. The loudness of the equipment or the speed of the candy that is fed into the cutter alike influences the weight. thither could also be a weight variation if in that location is a fluctuation in the temperature. 8.62.
) In 1992, the FAA conducted 86,991 pre-employment medicine tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1,143 were positive. (a) Construct a 95 percent confidence interval for the population proportion of positive drug tests. Â Â E = 1.96*sqrt [0.01314*(1-0.01314)/86,991] = 0.0007567.. 95% CI: 0.79615, 83671 (b) Why is the atomic rate 7 assumption not a problem, despite the real small time value of p? The normality assumption really is not a problem because the sample size is very lar ge. Even though the small value of p, p is n! ormally distributed by the Central Limit Theorem.If you necessity to pass water a full essay, order it on our website: BestEssayCheap.com
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